The photoelectric threshold wavelength of a metal is 230 nm. Determine the maximum kinetic energy in joule and in eV of the ejects electron for the metal surface when it is exposed to a radiation of wavelength 180 nm.

[Planck’s constant : h = 6.63 * 10^{-34} Js, Velocity of light : C = 3 * 10^{8} m/s.]

Advertisement Remove all ads

#### Solution

λ_{0} = 230 nm = 230 × 10^{−9}m,

λ = 180 nm = 180 × 10^{−9}m,

h = 6.63 × 10^{−34} J s, c = 3 × 10^{8}

m/s, K.E. (in joule and eV) = ?

Now,

∴ The maximum kinetic energy of the ejected electron is 2.402 × 10^{−19} J.

∴ The maximum kinetic energy of the ejected electron is 1.5 eV.

Concept: Einstein’s Equation - Particle Nature of Light

Is there an error in this question or solution?

#### APPEARS IN

Advertisement Remove all ads